Just answer this please right away?
1 - log a = log b - 5 log c .
Solve for a please??
the answer is not a number you should give as formula
1 - log a = log b - 5 log c:
1 = log a + log b - log c^5 = log a + log b + log c^-5
1 = log (abc^-5)
abc^-5 = 10
why should anyone answer your questions jerk?
I answered two of them, and you deleted them right afterwards, even after "promising" 10 points.
Homework cheaters like you should be banned.
[Can anybody help me to solve my problem here ??] - A New Kind of ::
So If you Know how use please tell me? My Problem Although you don't really need to since it is so simple, you can define your function f as follows -
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Jun 7, 2008 The victim is going thru a heck of a lot right now, just pray he survives, . Eighth grade was a really long time ago - for me.
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You are lazy and immoral.
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Then don't promise 10 points, and don't delete questions after people spend valuable time trying to help you, not to mention that you certainly can choose a best answer for any question you ask regardless of level, and you get points back for doing so!
using properties of logs:
log a - log b = log (a / b)
log (a^r) = r log a
1 - log a = log b - 5 log c
1 - log a = log b - log (c^5)
1 - log a = log (b / c^5)
1 - log (b / c^5) = log a
exponentiate both sides to the base 10 (assuming that log is the common log base 10)
10^(1 - log (b / c^5) = a
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