An oil company operates two refineries which produce Regular, Midgrade, and Premium grades of gasoline. The Washington refinery costs $750,000 a day to operate. It produces 45,000 gallons of Regular, 30,000 gallons of Midgrade, and 60,000 gallons of Premium grade gasoline per day.
Newsletter #81::
communities throughout this country is an issue as urgent as the lack math problem should take more than five minutes to solve, and if a problem takes
http://www.math.washington.edu/~warfield/news/news81.htmlHOME |
The Texas refinery $680,000 a day to operate. It produces 60,000 of Regular, 30,000 gallons of Midgrade, and 30,000 gallons of Premium grade gasoline per day. The oil company wants to produce gasoline at the following levels:
algebra help !!!urgent !!!? 1.A jet can travel 4550 km in 5 hours with ::
p: i=prt we actually did this problem in my math class circle p it helps a LOT n 4.) do in same way as above 5.) true 6.) p: i=prt we actually did
http://answers.yahoo.com/question/index?qid=20080528154553AAOgVARHOME |
How to Maximize Results With Effective Algebra Practice::
Lets look for example at the following math problem: Solving Algebra Word Problems Made Easy With a Lucid Explanation of the Method With Examples
http://ezinearticles.com/?How-to-Maximize-Results-With-Effective-Algebra-Practice&id=1753028HOME |
First we call the numbers of days operating for Washington X en for Texas Y.
Then the costs are calculated with C = 750,000 * X + 680,000 * Y
The constraints are:
45,000 * X + 60,000 * Y at least 900,000, but at most 1,800,000
30,000 * X + 30,000 * Y at most 1,050,000
Parents Rise Up Against A New Approach to Math::
increasingly urgent quest for stronger elementary math education. School in Woodbridge, third-graders used a mix of methods to solve word problems.
http://www.washingtonpost.com/wp-dyn/content/article/2008/02/18/AR2008021802244_pf.htmlHOME |
Trigonometry [Archive] - Math Help Forum::
Trig word problem. urgent triangle help! Help. Analytic Trig How do I solve this problem? Quick trig problem moments-with forces applied at an angle.
http://www.mathhelpforum.com/math-help/archive/f-14.htmlHOME |
60,000 * X + 30,000 * Y at least 600,000
Then you need to minimize the cost-formula while respecting the constraints.
washington refinery 20 days and the Texas refinery 15 days.
Your question is incomplete...
I think you can answer this problem.
Assume refinery 1 is open for x day s and refinery 2 is open for y days
Then
Cost = 750,000x + 680,000y
We also know from the number of gallons of each grade they need and how much they produce each day:
Regular
900,000<=45,000x + 60,000y and
45,000x +60,000y <= 1,800,000
which can be reduced to
60<=3x+4y and
3x+4y<= 120
Mid grade
30,000x+30,000y<=1,050,000
which can be reduced to
x+y<=35
Premium
600,000<=60,000x+30,000y
which can be reduced to
20<=2x+y
So you are left with
60<=3x+4y
3x+4y<= 120
x+y<=35
20<=2x+y
and your cost equation
Now it gets a little messy so I wont do it out, but what you need to do is solve the cost equation for y, plug that into the four equations solve them for c and graph each one. To graph you assume it to be c=equation then on the graph you "shade" either over or under the line depending on whether it is less than or greater than c. Hopefully there should be a point that is shaded by all four equations that is the lowest possible c (yaxis) that is the lowest cost and that will also give you x days, use the cost equation to then solve for the y days
 Red Hat's Rough Recovery From CFO Exit
 Windows Live Finds a New, Pre-installed Home |
HOME