Math Help - Calculus - Derivatives - Technical Tutoring::
Moreover, the value of the derivative must match what we expect from the limits What we would like to do is find the slope of a function at a point x0 as a
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1. f(x) = 4/(x^2)
what is the derivative when x=3?
2. if f(x) = 2+4x-3x^2
what is the derivative when x=4?
could someone please show me the steps to solve these?
Karls Calculus Tutor - Box 4.4x: Rules for Derivatives::
Rule 1) The Derivative of any constant is always zero. The number, 14, doesnt change no matter what else varies. So the derivative of 14 is zero.
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thank you!
f(x) = 4/(x^2)
f(x) = 4x^-2
f'(x) = 4(-2x^-3)
f'(x) = -8x^-3
f'(x) = -8/(x^3)
f'(x) = -8/[(3)^3]
f'(x) = -8/27
f(x) = 2 + 4x - 3x^2
f'(x) = 4 - 3(2x)
f'(x) = 4 - 6x
f'(x) = 4 - 6(4)
f'(x) = 4 - 24
f'(x) = -20
f(x)=4/(x^2)=4(x^-2)
f´(x)=-2*4(x^(-2-1))
f¨(x)=-8/(x^3)
f¨(3)=-8/27
f(x)=2+4x-3x^2
What Is A Financial Derivative::
The mysterious Derivative is no different, its actually pretty simple. You think there is a famine, war, water shortage, or whatever and the price of
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f´(x)=0+4-2*3x^(2-1)
f´(x)=4-6x
f´(4)=4-6*4=4-24=-20
1. f(x) = 4/(x^2) =4*x^-2
f'(x)=-8x^-3=-8/x^3
f'(3)=-8/3^3=-8/27
2. f(x) = 2+4x-3x^2
f'(x)=4-6x
f'(4)=4-6*4=-20
formula is f(x)=x^a then f'(x)=a*x^(a-1)
1. Let y = 4/x^2, so:
y = 4x^-2, and
dy/dx = -8x^-3
= -8/x^3.
When x = 3,
dy/dx = -8/3*3*3
= -8/27.
2. Let y = 2 + 4x - 3x^2
dy/dx = 4 - 6x
When x = 4,
dy/dx = 4 - 6 * 4
= 4 - 24
= -20.
(1) f(x) = 4/(x^2) =4x^(-2)
d(f(x)/dx = 4(-2)x^(-3) = -8/(x^3)
at x = 3
d(f(x)/dx = -8/(3^3) = -8/27
(2) f(x) = 2 + 4x - 3x^2
d(f(x))/dx = 0 + 4 - 6x = 4 - 6x
at x = 4
d(f(x))/dx = 4 - 6(4)= 4 - 24 = - 20
1. i hop you know the shortcut when dealing with derivatives because if you do not then you have to use (h+1) but with shortcut it is
-8x^-3and when x=3 then just plug in 3
for derivatives you take the power number and multiplyi it by the coefficient
2.
4-6x and when x=4 its 4-6(4)=-20
 Red Hat's Rough Recovery From CFO Exit
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